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@RamonAraujo
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All changes are in part d. They are detailed below

  1. In the summation result of the $E(M)$ calculation, the term $1/n$ inside the summation is wrong. Fixed to the correct term $1/i$ inside the summation.

  2. In the current solution, the summation result of $E(M)$ is stated as equal to $\log(n) + 0.577$. This expression is an approximation for the sum of the first $n$ terms of the harmonic series, and is valid only for large $n$. Since the problem did not explicitly state that there are many radioactive particles, I think it is best to write the result of $E(M)$ as a summation.

  3. Added the calculation of the variance of $M$.

@fifthist fifthist merged commit c9f7bf8 into fifthist:master Oct 25, 2025
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2 participants